3jk^2(2j^2+k)=

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Solution for 3jk^2(2j^2+k)= equation:


Simplifying
3jk2(2j2 + k) = 0
(2j2 * 3jk2 + k * 3jk2) = 0

Reorder the terms:
(3jk3 + 6j3k2) = 0
(3jk3 + 6j3k2) = 0

Solving
3jk3 + 6j3k2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '3jk2'.
3jk2(k + 2j2) = 0

Ignore the factor 3.

Subproblem 1

Set the factor 'jk2' equal to zero and attempt to solve: Simplifying jk2 = 0 Solving jk2 = 0 Move all terms containing j to the left, all other terms to the right. Simplifying jk2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(k + 2j2)' equal to zero and attempt to solve: Simplifying k + 2j2 = 0 Reorder the terms: 2j2 + k = 0 Solving 2j2 + k = 0 Move all terms containing j to the left, all other terms to the right. Add '-1k' to each side of the equation. 2j2 + k + -1k = 0 + -1k Combine like terms: k + -1k = 0 2j2 + 0 = 0 + -1k 2j2 = 0 + -1k Remove the zero: 2j2 = -1k Divide each side by '2'. j2 = -0.5k Simplifying j2 = -0.5k The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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